If resistance remains constant, doubling the voltage increases the power by a factor of four.

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Multiple Choice

If resistance remains constant, doubling the voltage increases the power by a factor of four.

Explanation:
When resistance stays the same, power in a resistor scales with the square of the voltage. Using P = V^2 / R, if you double the voltage, you get P' = (2V)^2 / R = 4V^2 / R = 4P. So power increases by a factor of four. (Equivalently, with P = I^2R and V = IR, doubling V doubles I, and P = I^2R becomes four times larger as well.) If the resistance isn’t constant, the factor could differ.

When resistance stays the same, power in a resistor scales with the square of the voltage. Using P = V^2 / R, if you double the voltage, you get P' = (2V)^2 / R = 4V^2 / R = 4P. So power increases by a factor of four. (Equivalently, with P = I^2R and V = IR, doubling V doubles I, and P = I^2R becomes four times larger as well.) If the resistance isn’t constant, the factor could differ.

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